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11044303133 = 31356267843
BaseRepresentation
bin10100100100100101…
…01011000100011101
31001111200210201201012
422102102223010131
5140104320200013
65023525425005
7540455012333
oct122222530435
931450721635
1011044303133
114758248456
12218286b165
131070169a16
1476ab23b53
154498e11a8
hex2924ab11d

11044303133 has 4 divisors (see below), whose sum is σ = 11400571008. Its totient is φ = 10688035260.

The previous prime is 11044303121. The next prime is 11044303157. The reversal of 11044303133 is 33130344011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11044303133 - 24 = 11044303117 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11044303099 and 11044303108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11044302133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 178133891 + ... + 178133952.

It is an arithmetic number, because the mean of its divisors is an integer number (2850142752).

Almost surely, 211044303133 is an apocalyptic number.

It is an amenable number.

11044303133 is a deficient number, since it is larger than the sum of its proper divisors (356267875).

11044303133 is an equidigital number, since it uses as much as digits as its factorization.

11044303133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 356267874.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 11044303133 its reverse (33130344011), we get a palindrome (44174647144).

The spelling of 11044303133 in words is "eleven billion, forty-four million, three hundred three thousand, one hundred thirty-three".

Divisors: 1 31 356267843 11044303133