Base | Representation |
---|---|
bin | 11001000111001011010010… |
… | …011110010100000100011111 |
3 | 112111001101002120102011021202 |
4 | 121013023102132110010133 |
5 | 103434004431433224411 |
6 | 1030521230435550115 |
7 | 32156224133143436 |
oct | 3107132236240437 |
9 | 474041076364252 |
10 | 110444320211231 |
11 | 3221119a533236 |
12 | 10478a2345b33b |
13 | 4981b15a39b56 |
14 | 1d3b76837a11d |
15 | cb7d9c01a83b |
hex | 6472d279411f |
110444320211231 has 8 divisors (see below), whose sum is σ = 113165326788864. Its totient is φ = 107724610903680.
The previous prime is 110444320211209. The next prime is 110444320211263. The reversal of 110444320211231 is 132112023444011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110444320211231 is a prime.
It is a super-3 number, since 3×1104443202112313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 110444320211194 and 110444320211203.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110444320219231) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 324145151 + ... + 324485696.
It is an arithmetic number, because the mean of its divisors is an integer number (14145665848608).
Almost surely, 2110444320211231 is an apocalyptic number.
110444320211231 is a deficient number, since it is larger than the sum of its proper divisors (2721006577633).
110444320211231 is an equidigital number, since it uses as much as digits as its factorization.
110444320211231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 648635041.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 110444320211231 its reverse (132112023444011), we get a palindrome (242556343655242).
The spelling of 110444320211231 in words is "one hundred ten trillion, four hundred forty-four billion, three hundred twenty million, two hundred eleven thousand, two hundred thirty-one".
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