Base | Representation |
---|---|
bin | 10100100101010100… |
… | …11110100101110001 |
3 | 1001112010112202211220 |
4 | 22102222132211301 |
5 | 140112414342343 |
6 | 5024311255253 |
7 | 540562032624 |
oct | 122252364561 |
9 | 31463482756 |
10 | 11050543473 |
11 | 476081a962 |
12 | 218497a529 |
13 | 1071543228 |
14 | 76b8a9dbb |
15 | 44a225183 |
hex | 292a9e971 |
11050543473 has 32 divisors (see below), whose sum is σ = 15960913920. Its totient is φ = 6775031040.
The previous prime is 11050543451. The next prime is 11050543481. The reversal of 11050543473 is 37434505011.
11050543473 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11050543473 - 210 = 11050542449 is a prime.
It is a super-2 number, since 2×110505434732 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11050563473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 491508 + ... + 513498.
It is an arithmetic number, because the mean of its divisors is an integer number (498778560).
Almost surely, 211050543473 is an apocalyptic number.
It is an amenable number.
11050543473 is a deficient number, since it is larger than the sum of its proper divisors (4910370447).
11050543473 is a wasteful number, since it uses less digits than its factorization.
11050543473 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22237.
The product of its (nonzero) digits is 25200, while the sum is 33.
The spelling of 11050543473 in words is "eleven billion, fifty million, five hundred forty-three thousand, four hundred seventy-three".
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