1105113401 has 4 divisors (see below), whose sum is σ = 1262986752. Its totient is φ = 947240052.

The previous prime is 1105113379. The next prime is 1105113403. The reversal of 1105113401 is 1043115011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1043115011 = 97 ⋅10753763.

It is a cyclic number.

It is not a de Polignac number, because 1105113401 - 2¹⁸ = 1104851257 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1105113401.

It is not an unprimeable number, because it can be changed into a prime (1105113403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78936665 + ... + 78936678.

It is an arithmetic number, because the mean of its divisors is an integer number (315746688).

Almost surely, 2^1105113401 is an apocalyptic number.

It is an amenable number.

1105113401 is a deficient number, since it is larger than the sum of its proper divisors (157873351).

1105113401 is an equidigital number, since it uses as much as digits as its factorization.

1105113401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 157873350.

The product of its (nonzero) digits is 60, while the sum is 17.

The square root of 1105113401 is about 33243.2459456053. The cubic root of 1105113401 is about 1033.8771773271.

Adding to 1105113401 its reverse (1043115011), we get a palindrome (2148228412).

The spelling of 1105113401 in words is "one billion, one hundred five million, one hundred thirteen thousand, four hundred one".