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11052121315 = 59722787879
BaseRepresentation
bin10100100101100000…
…11111110011100011
31001112020111221020111
422102300133303203
5140113320340230
65024405152151
7540611324014
oct122260376343
931466457214
1011052121315
1147616a8364
1221853bb657
131071976471
1476bb9b00b
1544a43792a
hex292c1fce3

11052121315 has 8 divisors (see below), whose sum is σ = 13399273440. Its totient is φ = 8750545152.

The previous prime is 11052121303. The next prime is 11052121319. The reversal of 11052121315 is 51312125011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11052121315 - 213 = 11052113123 is a prime.

It is a super-3 number, since 3×110521213153 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (11052121319) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11393455 + ... + 11394424.

It is an arithmetic number, because the mean of its divisors is an integer number (1674909180).

Almost surely, 211052121315 is an apocalyptic number.

11052121315 is a deficient number, since it is larger than the sum of its proper divisors (2347152125).

11052121315 is an equidigital number, since it uses as much as digits as its factorization.

11052121315 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22787981.

The product of its (nonzero) digits is 300, while the sum is 22.

Adding to 11052121315 its reverse (51312125011), we get a palindrome (62364246326).

The spelling of 11052121315 in words is "eleven billion, fifty-two million, one hundred twenty-one thousand, three hundred fifteen".

Divisors: 1 5 97 485 22787879 113939395 2210424263 11052121315