Search a number
-
+
11052254131 = 401152318097
BaseRepresentation
bin10100100101100010…
…00000001110110011
31001112020202200102121
422102301000032303
5140113334113011
65024412055111
7540612416152
oct122261001663
931466680377
1011052254131
114761789126
122185464497
1310719c1a59
1476bbd3599
1544a461e71
hex292c403b3

11052254131 has 8 divisors (see below), whose sum is σ = 11087703504. Its totient is φ = 11016844800.

The previous prime is 11052254123. The next prime is 11052254173. The reversal of 11052254131 is 13145225011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11052254131 - 23 = 11052254123 is a prime.

It is a super-2 number, since 2×110522541312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11052254096 and 11052254105.

It is not an unprimeable number, because it can be changed into a prime (11052251131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 601675 + ... + 619771.

It is an arithmetic number, because the mean of its divisors is an integer number (1385962938).

Almost surely, 211052254131 is an apocalyptic number.

11052254131 is a deficient number, since it is larger than the sum of its proper divisors (35449373).

11052254131 is a wasteful number, since it uses less digits than its factorization.

11052254131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20021.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 11052254131 its reverse (13145225011), we get a palindrome (24197479142).

The spelling of 11052254131 in words is "eleven billion, fifty-two million, two hundred fifty-four thousand, one hundred thirty-one".

Divisors: 1 401 1523 18097 610723 7256897 27561731 11052254131