Base | Representation |
---|---|
bin | 1010000011011011110010… |
… | …1010111011100001001111 |
3 | 1110010202121100212122110000 |
4 | 2200312330222323201033 |
5 | 2422102312223114210 |
6 | 35302105122015343 |
7 | 2220430206403353 |
oct | 240667452734117 |
9 | 43122540778400 |
10 | 11054116223055 |
11 | 358202a4782a4 |
12 | 12a64411a7553 |
13 | 622524bb9209 |
14 | 2a3044831463 |
15 | 1428225d0ac0 |
hex | a0dbcabb84f |
11054116223055 has 20 divisors (see below), whose sum is σ = 19815526859832. Its totient is φ = 5895528652080.
The previous prime is 11054116223023. The next prime is 11054116223081. The reversal of 11054116223055 is 55032261145011.
11054116223055 is a `hidden beast` number, since 1 + 1 + 0 + 5 + 411 + 6 + 2 + 230 + 5 + 5 = 666.
It is not a de Polignac number, because 11054116223055 - 25 = 11054116223023 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 13647056661 + ... + 13647057470.
Almost surely, 211054116223055 is an apocalyptic number.
11054116223055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11054116223055 is a deficient number, since it is larger than the sum of its proper divisors (8761410636777).
11054116223055 is an equidigital number, since it uses as much as digits as its factorization.
11054116223055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27294114148 (or 27294114139 counting only the distinct ones).
The product of its (nonzero) digits is 36000, while the sum is 36.
Adding to 11054116223055 its reverse (55032261145011), we get a palindrome (66086377368066).
The spelling of 11054116223055 in words is "eleven trillion, fifty-four billion, one hundred sixteen million, two hundred twenty-three thousand, fifty-five".
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