Base | Representation |
---|---|
bin | 1010000011011011110101… |
… | …0010101000011000110111 |
3 | 1110010202122002110101201021 |
4 | 2200312331102220120313 |
5 | 2422102322404133310 |
6 | 35302110133042011 |
7 | 2220430364020546 |
oct | 240667522503067 |
9 | 43122562411637 |
10 | 11054126630455 |
11 | 3582035336557 |
12 | 12a6444786307 |
13 | 6225270c133c |
14 | 2a3045d8015d |
15 | 1428234895da |
hex | a0dbd4a8637 |
11054126630455 has 16 divisors (see below), whose sum is σ = 13963189939200. Its totient is φ = 8377814823840.
The previous prime is 11054126630453. The next prime is 11054126630467. The reversal of 11054126630455 is 55403662145011.
11054126630455 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11054126630455 - 21 = 11054126630453 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11054126630453) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28113906 + ... + 28504384.
It is an arithmetic number, because the mean of its divisors is an integer number (872699371200).
Almost surely, 211054126630455 is an apocalyptic number.
11054126630455 is a deficient number, since it is larger than the sum of its proper divisors (2909063308745).
11054126630455 is a wasteful number, since it uses less digits than its factorization.
11054126630455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 688494.
The product of its (nonzero) digits is 432000, while the sum is 43.
Adding to 11054126630455 its reverse (55403662145011), we get a palindrome (66457788775466).
The spelling of 11054126630455 in words is "eleven trillion, fifty-four billion, one hundred twenty-six million, six hundred thirty thousand, four hundred fifty-five".
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