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11055411140143 = 17401635331943
BaseRepresentation
bin1010000011100000100111…
…0110101001011000101111
31110010212221121111020202011
42200320021312221120233
52422112440222441033
635302441420342051
72220504252124006
oct240701166513057
943125847436664
1011055411140143
113582634413707
1212a67429a4927
136226a0264746
142a31287cbc3d
1514289b119ccd
hexa0e09da962f

11055411140143 has 4 divisors (see below), whose sum is σ = 11056046489488. Its totient is φ = 11054775790800.

The previous prime is 11055411140129. The next prime is 11055411140167. The reversal of 11055411140143 is 34104111455011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11055411140143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11055411110143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 317648571 + ... + 317683372.

It is an arithmetic number, because the mean of its divisors is an integer number (2764011622372).

Almost surely, 211055411140143 is an apocalyptic number.

11055411140143 is a deficient number, since it is larger than the sum of its proper divisors (635349345).

11055411140143 is an equidigital number, since it uses as much as digits as its factorization.

11055411140143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 635349344.

The product of its (nonzero) digits is 4800, while the sum is 31.

Adding to 11055411140143 its reverse (34104111455011), we get a palindrome (45159522595154).

The spelling of 11055411140143 in words is "eleven trillion, fifty-five billion, four hundred eleven million, one hundred forty thousand, one hundred forty-three".

Divisors: 1 17401 635331943 11055411140143