Base | Representation |
---|---|
bin | 1010000011111101011011… |
… | …0110010110111010001011 |
3 | 1110011121220121210101020210 |
4 | 2200333112312112322023 |
5 | 2422224310203023120 |
6 | 35310201103452203 |
7 | 2221200024662655 |
oct | 240772666267213 |
9 | 43147817711223 |
10 | 11063145361035 |
11 | 35859431602a9 |
12 | 12a8140bb7063 |
13 | 6233336cc001 |
14 | 2a365da6d6d5 |
15 | 142ba0115ce0 |
hex | a0fd6d96e8b |
11063145361035 has 16 divisors (see below), whose sum is σ = 18470642690304. Its totient is φ = 5643807488352.
The previous prime is 11063145361033. The next prime is 11063145361067. The reversal of 11063145361035 is 53016354136011.
It is not a de Polignac number, because 11063145361035 - 21 = 11063145361033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11063145360984 and 11063145361002.
It is not an unprimeable number, because it can be changed into a prime (11063145361031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16033543657 + ... + 16033544346.
It is an arithmetic number, because the mean of its divisors is an integer number (1154415168144).
Almost surely, 211063145361035 is an apocalyptic number.
11063145361035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11063145361035 is a deficient number, since it is larger than the sum of its proper divisors (7407497329269).
11063145361035 is a wasteful number, since it uses less digits than its factorization.
11063145361035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32067088034.
The product of its (nonzero) digits is 97200, while the sum is 39.
Adding to 11063145361035 its reverse (53016354136011), we get a palindrome (64079499497046).
The spelling of 11063145361035 in words is "eleven trillion, sixty-three billion, one hundred forty-five million, three hundred sixty-one thousand, thirty-five".
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