Base | Representation |
---|---|
bin | 10100100110111101… |
… | …11000011011000101 |
3 | 1001120002101200212210 |
4 | 22103132320123011 |
5 | 140124423441043 |
6 | 5025521534033 |
7 | 541116556230 |
oct | 122336703305 |
9 | 31502350783 |
10 | 11064280773 |
11 | 47685529a7 |
12 | 21894a4319 |
13 | 1074342c00 |
14 | 76d644417 |
15 | 44b53a633 |
hex | 2937b86c5 |
11064280773 has 192 divisors, whose sum is σ = 20388249600. Its totient is φ = 5204010240.
The previous prime is 11064280771. The next prime is 11064280789. The reversal of 11064280773 is 37708246011.
It is not a de Polignac number, because 11064280773 - 21 = 11064280771 is a prime.
It is a super-3 number, since 3×110642807733 (a number of 31 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11064280771) by changing a digit.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 140054148 + ... + 140054226.
It is an arithmetic number, because the mean of its divisors is an integer number (106188800).
Almost surely, 211064280773 is an apocalyptic number.
11064280773 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11064280773 is a deficient number, since it is larger than the sum of its proper divisors (9323968827).
11064280773 is a wasteful number, since it uses less digits than its factorization.
11064280773 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 232 (or 219 counting only the distinct ones).
The product of its (nonzero) digits is 56448, while the sum is 39.
The spelling of 11064280773 in words is "eleven billion, sixty-four million, two hundred eighty thousand, seven hundred seventy-three".
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