Base | Representation |
---|---|
bin | 10100100111110011… |
… | …10110100100001111 |
3 | 1001120120200220111002 |
4 | 22103321312210033 |
5 | 140133231213210 |
6 | 5030333250515 |
7 | 541233634262 |
oct | 122371664417 |
9 | 31516626432 |
10 | 11071351055 |
11 | 4771541a06 |
12 | 218b933a3b |
13 | 107594a0cb |
14 | 770564cd9 |
15 | 44be854a5 |
hex | 293e7690f |
11071351055 has 4 divisors (see below), whose sum is σ = 13285621272. Its totient is φ = 8857080840.
The previous prime is 11071351051. The next prime is 11071351063. The reversal of 11071351055 is 55015317011.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 11071351055 - 22 = 11071351051 is a prime.
It is a super-2 number, since 2×110713510552 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11071351051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1107135101 + ... + 1107135110.
It is an arithmetic number, because the mean of its divisors is an integer number (3321405318).
Almost surely, 211071351055 is an apocalyptic number.
11071351055 is a deficient number, since it is larger than the sum of its proper divisors (2214270217).
11071351055 is an equidigital number, since it uses as much as digits as its factorization.
11071351055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2214270216.
The product of its (nonzero) digits is 2625, while the sum is 29.
Adding to 11071351055 its reverse (55015317011), we get a palindrome (66086668066).
The spelling of 11071351055 in words is "eleven billion, seventy-one million, three hundred fifty-one thousand, fifty-five".
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