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1108054671361 = 11100732242851
BaseRepresentation
bin10000000111111101001…
…101001000000000000001
310220221002020100110122021
4100013331031020000001
5121123243443440421
62205011105041441
7143024425206301
oct20077515100001
93827066313567
101108054671361
11397a17a7a890
1215a8b9326281
1380648750ac1
143b8b7123601
151dc52b9a341
hex101fd348001

1108054671361 has 4 divisors (see below), whose sum is σ = 1208786914224. Its totient is φ = 1007322428500.

The previous prime is 1108054671337. The next prime is 1108054671391. The reversal of 1108054671361 is 1631764508011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1108054671361 - 223 = 1108046282753 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1108054671391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50366121415 + ... + 50366121436.

It is an arithmetic number, because the mean of its divisors is an integer number (302196728556).

Almost surely, 21108054671361 is an apocalyptic number.

1108054671361 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1108054671361 is a deficient number, since it is larger than the sum of its proper divisors (100732242863).

1108054671361 is a wasteful number, since it uses less digits than its factorization.

1108054671361 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100732242862.

The product of its (nonzero) digits is 120960, while the sum is 43.

The spelling of 1108054671361 in words is "one trillion, one hundred eight billion, fifty-four million, six hundred seventy-one thousand, three hundred sixty-one".

Divisors: 1 11 100732242851 1108054671361