Search a number
-
+
11099129901 = 33699709967
BaseRepresentation
bin10100101011000111…
…10100100000101101
31001122111222012220020
422111203310200231
5140212334124101
65033204512353
7542022022206
oct122543644055
931574865806
1011099129901
114786195632
1221990ab6b9
13107b6250b2
147741165ad
1544e621136
hex2958f482d

11099129901 has 4 divisors (see below), whose sum is σ = 14798839872. Its totient is φ = 7399419932.

The previous prime is 11099129887. The next prime is 11099129953. The reversal of 11099129901 is 10992199011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10992199011 = 33664066337.

It is a cyclic number.

It is not a de Polignac number, because 11099129901 - 25 = 11099129869 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11099129971) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1849854981 + ... + 1849854986.

It is an arithmetic number, because the mean of its divisors is an integer number (3699709968).

Almost surely, 211099129901 is an apocalyptic number.

It is an amenable number.

11099129901 is a deficient number, since it is larger than the sum of its proper divisors (3699709971).

11099129901 is an equidigital number, since it uses as much as digits as its factorization.

11099129901 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3699709970.

The product of its (nonzero) digits is 13122, while the sum is 42.

The spelling of 11099129901 in words is "eleven billion, ninety-nine million, one hundred twenty-nine thousand, nine hundred one".

Divisors: 1 3 3699709967 11099129901