11100101011020 has 192 divisors, whose sum is σ = 39478876631040. Its totient is φ = 2536404109056.

The previous prime is 11100101011007. The next prime is 11100101011061. The reversal of 11100101011020 is 2011010100111.

It is a super-3 number, since 3×11100101011020³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a junction number, because it is equal to n+sod(n) for n = 11100101010993 and 11100101011011.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 12197334 + ... + 13075746.

It is an arithmetic number, because the mean of its divisors is an integer number (205619149120).

Almost surely, 2^{11100101011020} is an apocalyptic number.

11100101011020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11100101011020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19739438315520).

11100101011020 is an abundant number, since it is smaller than the sum of its proper divisors (28378775620020).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11100101011020 is a wasteful number, since it uses less digits than its factorization.

11100101011020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 881781 (or 881773 counting only the distinct ones).

The product of its (nonzero) digits is 2, while the sum is 9.

Adding to 11100101011020 its reverse (2011010100111), we get a palindrome (13111111111131).

The spelling of 11100101011020 in words is "eleven trillion, one hundred billion, one hundred one million, eleven thousand, twenty".