111002012113 has 4 divisors (see below), whose sum is σ = 111737124928. Its totient is φ = 110266899300.

The previous prime is 111002012101. The next prime is 111002012117. The reversal of 111002012113 is 311210200111.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311210200111 = 89917 ⋅3461083.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111002012113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111002012093 and 111002012102.

It is not an unprimeable number, because it can be changed into a prime (111002012117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 367556181 + ... + 367556482.

It is an arithmetic number, because the mean of its divisors is an integer number (27934281232).

Almost surely, 2^111002012113 is an apocalyptic number.

It is an amenable number.

111002012113 is a deficient number, since it is larger than the sum of its proper divisors (735112815).

111002012113 is an equidigital number, since it uses as much as digits as its factorization.

111002012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 735112814.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 111002012113 its reverse (311210200111), we get a palindrome (422212212224).

The spelling of 111002012113 in words is "one hundred eleven billion, two million, twelve thousand, one hundred thirteen".