Base | Representation |
---|---|
bin | 11001001111010010110001… |
… | …011010000100101111001000 |
3 | 112120000200211222120021211010 |
4 | 121033102301122010233020 |
5 | 104022124310431401300 |
6 | 1032025355500403520 |
7 | 32244431536261323 |
oct | 3117226132045710 |
9 | 476020758507733 |
10 | 111002111200200 |
11 | 32406804a54040 |
12 | 10548b525465a0 |
13 | 49c25b9a79a8c |
14 | 1d5a76090b7ba |
15 | cc76464a4a50 |
hex | 64f4b1684bc8 |
111002111200200 has 384 divisors, whose sum is σ = 377712394859520. Its totient is φ = 26743113139200.
The previous prime is 111002111200181. The next prime is 111002111200237. The reversal of 111002111200200 is 2002111200111.
111002111200200 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×1110021112002003 (a number of 43 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 10066387087 + ... + 10066398113.
It is an arithmetic number, because the mean of its divisors is an integer number (983626028280).
Almost surely, 2111002111200200 is an apocalyptic number.
111002111200200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 111002111200200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (188856197429760).
111002111200200 is an abundant number, since it is smaller than the sum of its proper divisors (266710283659320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111002111200200 is a wasteful number, since it uses less digits than its factorization.
111002111200200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20357 (or 20348 counting only the distinct ones).
The product of its (nonzero) digits is 8, while the sum is 12.
Adding to 111002111200200 its reverse (2002111200111), we get a palindrome (113004222400311).
The spelling of 111002111200200 in words is "one hundred eleven trillion, two billion, one hundred eleven million, two hundred thousand, two hundred".
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