11100212113 has 4 divisors (see below), whose sum is σ = 11103991920. Its totient is φ = 11096432308.

The previous prime is 11100212087. The next prime is 11100212141. The reversal of 11100212113 is 31121200111.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11100212113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11100212093 and 11100212102.

It is not an unprimeable number, because it can be changed into a prime (11100212153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1885495 + ... + 1891372.

It is an arithmetic number, because the mean of its divisors is an integer number (2775997980).

Almost surely, 2^11100212113 is an apocalyptic number.

It is an amenable number.

11100212113 is a deficient number, since it is larger than the sum of its proper divisors (3779807).

11100212113 is an equidigital number, since it uses as much as digits as its factorization.

11100212113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3779806.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 11100212113 its reverse (31121200111), we get a palindrome (42221412224).

The spelling of 11100212113 in words is "eleven billion, one hundred million, two hundred twelve thousand, one hundred thirteen".