Base | Representation |
---|---|
bin | 10000001001110010011… |
… | …010111000011101100010 |
3 | 10221010011021202002020211 |
4 | 100021302122320131202 |
5 | 121141310412241002 |
6 | 2205534154524334 |
7 | 143124234424033 |
oct | 20116232703542 |
9 | 3833137662224 |
10 | 1110021212002 |
11 | 39883704398a |
12 | 15b167a366aa |
13 | 8089ccb1711 |
14 | 3ba2238ca8a |
15 | 1dd1a64ddd7 |
hex | 102726b8762 |
1110021212002 has 4 divisors (see below), whose sum is σ = 1665031818006. Its totient is φ = 555010606000.
The previous prime is 1110021211991. The next prime is 1110021212081. The reversal of 1110021212002 is 2002121200111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 618156040441 + 491865171561 = 786229^2 + 701331^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277505302999 + ... + 277505303002.
Almost surely, 21110021212002 is an apocalyptic number.
1110021212002 is a deficient number, since it is larger than the sum of its proper divisors (555010606004).
1110021212002 is an equidigital number, since it uses as much as digits as its factorization.
1110021212002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 555010606003.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 1110021212002 its reverse (2002121200111), we get a palindrome (3112142412113).
The spelling of 1110021212002 in words is "one trillion, one hundred ten billion, twenty-one million, two hundred twelve thousand, two".
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