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11100231103 = 13853863931
BaseRepresentation
bin10100101011010000…
…00001010110111111
31001122121001011110111
422111220001112333
5140213124343403
65033244250451
7542034256543
oct122550012677
931577034414
1011100231103
114786877a15
122199540a27
13107b91c3b0
14774321a23
1544e78c56d
hex295a015bf

11100231103 has 4 divisors (see below), whose sum is σ = 11954095048. Its totient is φ = 10246367160.

The previous prime is 11100231067. The next prime is 11100231127. The reversal of 11100231103 is 30113200111.

11100231103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11100231103 - 213 = 11100222911 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (13), and also a Moran number because the ratio is a prime number: 853863931 = 11100231103 / (1 + 1 + 1 + 0 + 0 + 2 + 3 + 1 + 1 + 0 + 3).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11100231133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 426931953 + ... + 426931978.

It is an arithmetic number, because the mean of its divisors is an integer number (2988523762).

Almost surely, 211100231103 is an apocalyptic number.

11100231103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11100231103 is a deficient number, since it is larger than the sum of its proper divisors (853863945).

11100231103 is an equidigital number, since it uses as much as digits as its factorization.

11100231103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 853863944.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11100231103 its reverse (30113200111), we get a palindrome (41213431214).

The spelling of 11100231103 in words is "eleven billion, one hundred million, two hundred thirty-one thousand, one hundred three".

Divisors: 1 13 853863931 11100231103