Base | Representation |
---|---|
bin | 1010000110000111111000… |
… | …1011000110101100101111 |
3 | 1110022011211212000012000211 |
4 | 2201201332023012230233 |
5 | 2423331414424124403 |
6 | 35335225121003251 |
7 | 2223654042016060 |
oct | 241417613065457 |
9 | 43264755005024 |
10 | 11100312333103 |
11 | 359a685a22544 |
12 | 12b3394183527 |
13 | 6269a785c086 |
14 | 2a5387c9a567 |
15 | 143b2803c06d |
hex | a187e2c6b2f |
11100312333103 has 8 divisors (see below), whose sum is σ = 12687367532672. Its totient is φ = 9513581207256.
The previous prime is 11100312333091. The next prime is 11100312333181. The reversal of 11100312333103 is 30133321300111.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11100312333103 - 221 = 11100310235951 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11100312333503) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 80945025 + ... + 81082042.
It is an arithmetic number, because the mean of its divisors is an integer number (1585920941584).
Almost surely, 211100312333103 is an apocalyptic number.
11100312333103 is a deficient number, since it is larger than the sum of its proper divisors (1587055199569).
11100312333103 is an equidigital number, since it uses as much as digits as its factorization.
11100312333103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 162036861.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 11100312333103 its reverse (30133321300111), we get a palindrome (41233633633214).
The spelling of 11100312333103 in words is "eleven trillion, one hundred billion, three hundred twelve million, three hundred thirty-three thousand, one hundred three".
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