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11100342133 = 23482623571
BaseRepresentation
bin10100101011010000…
…11100011101110101
31001122121020210202201
422111220130131311
5140213141422013
65033250504501
7542035231336
oct122550343565
931577223681
1011100342133
114786943381
122199595131
13107b95aaaa
1477435028d
1544e7b03dd
hex295a1c775

11100342133 has 4 divisors (see below), whose sum is σ = 11582965728. Its totient is φ = 10617718540.

The previous prime is 11100342131. The next prime is 11100342191. The reversal of 11100342133 is 33124300111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11100342133 - 21 = 11100342131 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11100342133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11100342131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 241311763 + ... + 241311808.

It is an arithmetic number, because the mean of its divisors is an integer number (2895741432).

Almost surely, 211100342133 is an apocalyptic number.

It is an amenable number.

11100342133 is a deficient number, since it is larger than the sum of its proper divisors (482623595).

11100342133 is an equidigital number, since it uses as much as digits as its factorization.

11100342133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 482623594.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 11100342133 its reverse (33124300111), we get a palindrome (44224642244).

The spelling of 11100342133 in words is "eleven billion, one hundred million, three hundred forty-two thousand, one hundred thirty-three".

Divisors: 1 23 482623571 11100342133