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111004030023 = 3731494733911
BaseRepresentation
bin110011101100001011…
…0110001010001000111
3101121112001122222122020
41213120112301101013
53304314012430043
6122554453334223
711006532454455
oct1473026612107
9347461588566
10111004030023
1143092976797
121961b037373
13a610518503
14553069d9d5
152d4a322e83
hex19d85b1447

111004030023 has 16 divisors (see below), whose sum is σ = 150047306496. Its totient is φ = 72981915840.

The previous prime is 111004030019. The next prime is 111004030043. The reversal of 111004030023 is 320030400111.

It is not a de Polignac number, because 111004030023 - 22 = 111004030019 is a prime.

It is a super-3 number, since 3×1110040300233 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111004029984 and 111004030011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111004030043) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3256438 + ... + 3290348.

It is an arithmetic number, because the mean of its divisors is an integer number (9377956656).

Almost surely, 2111004030023 is an apocalyptic number.

111004030023 is a deficient number, since it is larger than the sum of its proper divisors (39043276473).

111004030023 is a wasteful number, since it uses less digits than its factorization.

111004030023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48934.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 111004030023 its reverse (320030400111), we get a palindrome (431034430134).

The spelling of 111004030023 in words is "one hundred eleven billion, four million, thirty thousand, twenty-three".

Divisors: 1 3 73 219 14947 33911 44841 101733 1091131 2475503 3273393 7426509 506867717 1520603151 37001343341 111004030023