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11100432133 = 71585776019
BaseRepresentation
bin10100101011010001…
…10010011100000101
31001122121102101020001
422111220302130011
5140213202312013
65033252441301
7542036054620
oct122550623405
931577371201
1011100432133
1147869a4a5a
122199619231
13107b98ca4b
14774374db7
1544e7cbddd
hex295a32705

11100432133 has 4 divisors (see below), whose sum is σ = 12686208160. Its totient is φ = 9514656108.

The previous prime is 11100432107. The next prime is 11100432163. The reversal of 11100432133 is 33123400111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11100432133 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11100432133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11100432163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 792888003 + ... + 792888016.

It is an arithmetic number, because the mean of its divisors is an integer number (3171552040).

Almost surely, 211100432133 is an apocalyptic number.

It is an amenable number.

11100432133 is a deficient number, since it is larger than the sum of its proper divisors (1585776027).

11100432133 is an equidigital number, since it uses as much as digits as its factorization.

11100432133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1585776026.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 11100432133 its reverse (33123400111), we get a palindrome (44223832244).

The spelling of 11100432133 in words is "eleven billion, one hundred million, four hundred thirty-two thousand, one hundred thirty-three".

Divisors: 1 7 1585776019 11100432133