Base | Representation |
---|---|
bin | 10000001001110100001… |
… | …100100001000011100111 |
3 | 10221010020100210111110102 |
4 | 100021310030201003213 |
5 | 121141341024004201 |
6 | 2205541141214315 |
7 | 143125045552103 |
oct | 20116414410347 |
9 | 3833210714412 |
10 | 1110051000551 |
11 | 39885193a519 |
12 | 15b175a0139b |
13 | 808a621138c |
14 | 3ba26304903 |
15 | 1dd1d08526b |
hex | 102743210e7 |
1110051000551 has 4 divisors (see below), whose sum is σ = 1110110149512. Its totient is φ = 1109991851592.
The previous prime is 1110051000547. The next prime is 1110051000593. The reversal of 1110051000551 is 1550001500111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1110051000551 - 22 = 1110051000547 is a prime.
It is a super-3 number, since 3×11100510005513 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1110051000151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29546321 + ... + 29583866.
It is an arithmetic number, because the mean of its divisors is an integer number (277527537378).
Almost surely, 21110051000551 is an apocalyptic number.
1110051000551 is a deficient number, since it is larger than the sum of its proper divisors (59148961).
1110051000551 is an equidigital number, since it uses as much as digits as its factorization.
1110051000551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59148960.
The product of its (nonzero) digits is 125, while the sum is 20.
Adding to 1110051000551 its reverse (1550001500111), we get a palindrome (2660052500662).
The spelling of 1110051000551 in words is "one trillion, one hundred ten billion, fifty-one million, five hundred fifty-one", and thus it is an aban number.
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