Base | Representation |
---|---|
bin | 10000001001110111110… |
… | …101001110010000111101 |
3 | 10221010101121120202021022 |
4 | 100021313311032100331 |
5 | 121142002133100013 |
6 | 2205551200513525 |
7 | 143126416223150 |
oct | 20116765162075 |
9 | 3833347522238 |
10 | 1110112003133 |
11 | 398883315681 |
12 | 15b19231b8a5 |
13 | 808b5a4c793 |
14 | 3ba30463c97 |
15 | 1dd235d5008 |
hex | 10277d4e43d |
1110112003133 has 4 divisors (see below), whose sum is σ = 1268699432160. Its totient is φ = 951524574108.
The previous prime is 1110112003103. The next prime is 1110112003151. The reversal of 1110112003133 is 3313002110111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1110112003133 - 226 = 1110044894269 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1110112003103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79293714503 + ... + 79293714516.
It is an arithmetic number, because the mean of its divisors is an integer number (317174858040).
Almost surely, 21110112003133 is an apocalyptic number.
It is an amenable number.
1110112003133 is a deficient number, since it is larger than the sum of its proper divisors (158587429027).
1110112003133 is an equidigital number, since it uses as much as digits as its factorization.
1110112003133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 158587429026.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1110112003133 its reverse (3313002110111), we get a palindrome (4423114113244).
The spelling of 1110112003133 in words is "one trillion, one hundred ten billion, one hundred twelve million, three thousand, one hundred thirty-three".
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