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1110131131999 = 4909226142011
BaseRepresentation
bin10000001001111000111…
…110001100011001011111
310221010102221120121010211
4100021320332030121133
5121142022032210444
62205553122513251
7143130040633351
oct20117076143137
93833387517124
101110131131999
113988930a045a
1215b198805827
13808b99b9536
143ba32c030d1
151dd25112c34
hex10278f8c65f

1110131131999 has 4 divisors (see below), whose sum is σ = 1110357278920. Its totient is φ = 1109904985080.

The previous prime is 1110131131979. The next prime is 1110131132119. The reversal of 1110131131999 is 9991311310111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1110131131999 is a prime.

It is a super-2 number, since 2×11101311319992 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1110131131979) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113066097 + ... + 113075914.

It is an arithmetic number, because the mean of its divisors is an integer number (277589319730).

Almost surely, 21110131131999 is an apocalyptic number.

1110131131999 is a deficient number, since it is larger than the sum of its proper divisors (226146921).

1110131131999 is an equidigital number, since it uses as much as digits as its factorization.

1110131131999 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 226146920.

The product of its (nonzero) digits is 6561, while the sum is 40.

The spelling of 1110131131999 in words is "one trillion, one hundred ten billion, one hundred thirty-one million, one hundred thirty-one thousand, nine hundred ninety-nine".

Divisors: 1 4909 226142011 1110131131999