Base | Representation |
---|---|
bin | 1010000110001011110010… |
… | …1000110010000000010111 |
3 | 1110022021112212221102102122 |
4 | 2201202330220302000113 |
5 | 2423341041214100210 |
6 | 35335521114330155 |
7 | 2224022025416234 |
oct | 241427450620027 |
9 | 43267485842378 |
10 | 11101360300055 |
11 | 35a0073528633 |
12 | 12b362712995b |
13 | 626b139c216c |
14 | 2a544713278b |
15 | 143b8a045b55 |
hex | a18bca32017 |
11101360300055 has 4 divisors (see below), whose sum is σ = 13321632360072. Its totient is φ = 8881088240040.
The previous prime is 11101360300033. The next prime is 11101360300103. The reversal of 11101360300055 is 55000306310111.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 11101360300055 - 234 = 11084180430871 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11101360299997 and 11101360300033.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1110136030001 + ... + 1110136030010.
It is an arithmetic number, because the mean of its divisors is an integer number (3330408090018).
Almost surely, 211101360300055 is an apocalyptic number.
11101360300055 is a deficient number, since it is larger than the sum of its proper divisors (2220272060017).
11101360300055 is an equidigital number, since it uses as much as digits as its factorization.
11101360300055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2220272060016.
The product of its (nonzero) digits is 1350, while the sum is 26.
Adding to 11101360300055 its reverse (55000306310111), we get a palindrome (66101666610166).
The spelling of 11101360300055 in words is "eleven trillion, one hundred one billion, three hundred sixty million, three hundred thousand, fifty-five".
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