11101400113 has 4 divisors (see below), whose sum is σ = 11267092720. Its totient is φ = 10935707508.

The previous prime is 11101400099. The next prime is 11101400131. The reversal of 11101400113 is 31100410111.

It is a happy number.

11101400113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11101400113 - 2¹³ = 11101391921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11101400093 and 11101400102.

It is not an unprimeable number, because it can be changed into a prime (11101400813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82846203 + ... + 82846336.

It is an arithmetic number, because the mean of its divisors is an integer number (2816773180).

Almost surely, 2^11101400113 is an apocalyptic number.

It is an amenable number.

11101400113 is a deficient number, since it is larger than the sum of its proper divisors (165692607).

11101400113 is an equidigital number, since it uses as much as digits as its factorization.

11101400113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 165692606.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 11101400113 its reverse (31100410111), we get a palindrome (42201810224).

The spelling of 11101400113 in words is "eleven billion, one hundred one million, four hundred thousand, one hundred thirteen".