11101414013 has 4 divisors (see below), whose sum is σ = 11104617660. Its totient is φ = 11098210368.

The previous prime is 11101413997. The next prime is 11101414063. The reversal of 11101414013 is 31041410111.

11101414013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31041410111 = 109 ⋅284783579.

It can be written as a sum of positive squares in 2 ways, for example, as 2991871204 + 8109542809 = 54698^2 + 90053^2 .

It is a cyclic number.

It is not a de Polignac number, because 11101414013 - 2⁴ = 11101413997 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11101413982 and 11101414000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11101414063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1596620 + ... + 1603557.

It is an arithmetic number, because the mean of its divisors is an integer number (2776154415).

Almost surely, 2^11101414013 is an apocalyptic number.

It is an amenable number.

11101414013 is a deficient number, since it is larger than the sum of its proper divisors (3203647).

11101414013 is an equidigital number, since it uses as much as digits as its factorization.

11101414013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3203646.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11101414013 its reverse (31041410111), we get a palindrome (42142824124).

The spelling of 11101414013 in words is "eleven billion, one hundred one million, four hundred fourteen thousand, thirteen".