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11102110101120 = 273537383408041
BaseRepresentation
bin1010000110001110100101…
…0101000010111010000000
31110022100111010211021010110
42201203221111002322000
52423344110141213440
635340123341231320
72224046431546203
oct241435125027200
943270433737113
1011102110101120
1135a04187a2235
1212b37b6262540
13626c0314a22c
142a54b895193a
15143bd0ca4080
hexa18e9542e80

11102110101120 has 256 divisors, whose sum is σ = 36439391047680. Its totient is φ = 2873019432960.

The previous prime is 11102110101101. The next prime is 11102110101151. The reversal of 11102110101120 is 2110101120111.

It is a super-3 number, since 3×111021101011203 (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a junction number, because it is equal to n+sod(n) for n = 11102110101096 and 11102110101105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27004300 + ... + 27412340.

It is an arithmetic number, because the mean of its divisors is an integer number (142341371280).

Almost surely, 211102110101120 is an apocalyptic number.

11102110101120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11102110101120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18219695523840).

11102110101120 is an abundant number, since it is smaller than the sum of its proper divisors (25337280946560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11102110101120 is a wasteful number, since it uses less digits than its factorization.

11102110101120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 408483 (or 408471 counting only the distinct ones).

The product of its (nonzero) digits is 4, while the sum is 12.

Adding to 11102110101120 its reverse (2110101120111), we get a palindrome (13212211221231).

The spelling of 11102110101120 in words is "eleven trillion, one hundred two billion, one hundred ten million, one hundred one thousand, one hundred twenty".