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11102431402 = 25551215701
BaseRepresentation
bin10100101011100000…
…11010100010101010
31001122202011221201001
422111300122202222
5140214210301102
65033403345214
7542062052446
oct122560324252
931582157631
1011102431402
114788040047
12219a22220a
13107c20ca4a
14774735826
1544ea74487
hex295c1a8aa

11102431402 has 4 divisors (see below), whose sum is σ = 16653647106. Its totient is φ = 5551215700.

The previous prime is 11102431399. The next prime is 11102431423. The reversal of 11102431402 is 20413420111.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20413420111 = 72916202873.

It can be written as a sum of positive squares in only one way, i.e., 6959063241 + 4143368161 = 83421^2 + 64369^2 .

It is a super-2 number, since 2×111024314022 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11102431402.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2775607849 + ... + 2775607852.

Almost surely, 211102431402 is an apocalyptic number.

11102431402 is a deficient number, since it is larger than the sum of its proper divisors (5551215704).

11102431402 is an equidigital number, since it uses as much as digits as its factorization.

11102431402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5551215703.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 11102431402 its reverse (20413420111), we get a palindrome (31515851513).

The spelling of 11102431402 in words is "eleven billion, one hundred two million, four hundred thirty-one thousand, four hundred two".

Divisors: 1 2 5551215701 11102431402