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111031101022013 = 176531241236589
BaseRepresentation
bin11001001111101101110001…
…010101011101111100111101
3112120010110200100000211020022
4121033231301111131330331
5104023113143330201023
61032050552245101525
732246506121555264
oct3117556125357475
9476113610024208
10111031101022013
1132418030a52267
12105526a30b78a5
1349c5259a7ccb3
141d5bd10b195db
15cc829158b7c8
hex64fb7155df3d

111031101022013 has 4 divisors (see below), whose sum is σ = 117562342258620. Its totient is φ = 104499859785408.

The previous prime is 111031101021983. The next prime is 111031101022043. The reversal of 111031101022013 is 310220101130111.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (111031101021983) and next prime (111031101022043).

It can be written as a sum of positive squares in 2 ways, for example, as 44778875656804 + 66252225365209 = 6691702^2 + 8139547^2 .

It is a cyclic number.

It is not a de Polignac number, because 111031101022013 - 234 = 111013921152829 is a prime.

It is a super-2 number, since 2×1110311010220132 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (17), and also a Moran number because the ratio is a prime number: 6531241236589 = 111031101022013 / (1 + 1 + 1 + 0 + 3 + 1 + 1 + 0 + 1 + 0 + 2 + 2 + 0 + 1 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111031101021982 and 111031101022000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111031101022043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3265620618278 + ... + 3265620618311.

It is an arithmetic number, because the mean of its divisors is an integer number (29390585564655).

Almost surely, 2111031101022013 is an apocalyptic number.

It is an amenable number.

111031101022013 is a deficient number, since it is larger than the sum of its proper divisors (6531241236607).

111031101022013 is an equidigital number, since it uses as much as digits as its factorization.

111031101022013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6531241236606.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 111031101022013 its reverse (310220101130111), we get a palindrome (421251202152124).

The spelling of 111031101022013 in words is "one hundred eleven trillion, thirty-one billion, one hundred one million, twenty-two thousand, thirteen".

Divisors: 1 17 6531241236589 111031101022013