Base | Representation |
---|---|
bin | 11001001111101101110010… |
… | …011101111001101100011101 |
3 | 112120010110201122202111212120 |
4 | 121033231302131321230131 |
5 | 104023113213210310023 |
6 | 1032050554204053153 |
7 | 32246506442141010 |
oct | 3117556235715435 |
9 | 476113648674776 |
10 | 111031120010013 |
11 | 32418040741225 |
12 | 105526a95341b9 |
13 | 49c526099a8b8 |
14 | 1d5bd1345d377 |
15 | cc829308c8e3 |
hex | 64fb72779b1d |
111031120010013 has 16 divisors (see below), whose sum is σ = 169190722007040. Its totient is φ = 63446187830256.
The previous prime is 111031120010009. The next prime is 111031120010017. The reversal of 111031120010013 is 310010021130111.
It is an interprime number because it is at equal distance from previous prime (111031120010009) and next prime (111031120010017).
It is not a de Polignac number, because 111031120010013 - 22 = 111031120010009 is a prime.
It is a super-2 number, since 2×1110311200100132 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 111031120009974 and 111031120010001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111031120010017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1497256 + ... + 14976782.
It is an arithmetic number, because the mean of its divisors is an integer number (10574420125440).
Almost surely, 2111031120010013 is an apocalyptic number.
It is an amenable number.
111031120010013 is a deficient number, since it is larger than the sum of its proper divisors (58159601997027).
111031120010013 is a wasteful number, since it uses less digits than its factorization.
111031120010013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13871776.
The product of its (nonzero) digits is 18, while the sum is 15.
Adding to 111031120010013 its reverse (310010021130111), we get a palindrome (421041141140124).
The spelling of 111031120010013 in words is "one hundred eleven trillion, thirty-one billion, one hundred twenty million, ten thousand, thirteen".
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