1110320221301 has 4 divisors (see below), whose sum is σ = 1128522192204. Its totient is φ = 1092118250400.

The previous prime is 1110320221271. The next prime is 1110320221343. The reversal of 1110320221301 is 1031220230111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 637045018801 + 473275202500 = 798151^2 + 687950^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1110320221301 is a prime.

It is a super-4 number, since 4×1110320221301⁴ (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1110320221301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1110320221601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9100985360 + ... + 9100985481.

It is an arithmetic number, because the mean of its divisors is an integer number (282130548051).

Almost surely, 2^{1110320221301} is an apocalyptic number.

It is an amenable number.

1110320221301 is a deficient number, since it is larger than the sum of its proper divisors (18201970903).

1110320221301 is an equidigital number, since it uses as much as digits as its factorization.

1110320221301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18201970902.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1110320221301 its reverse (1031220230111), we get a palindrome (2141540451412).

The spelling of 1110320221301 in words is "one trillion, one hundred ten billion, three hundred twenty million, two hundred twenty-one thousand, three hundred one".