1110423214433 has 16 divisors (see below), whose sum is σ = 1241304884736. Its totient is φ = 986751512640.

The previous prime is 1110423214427. The next prime is 1110423214499. The reversal of 1110423214433 is 3344123240111.

It is a cyclic number.

It is not a de Polignac number, because 1110423214433 - 2²⁶ = 1110356105569 is a prime.

It is a super-2 number, since 2×1110423214433² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1110423214396 and 1110423214405.

It is not an unprimeable number, because it can be changed into a prime (1110423214423) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14859341 + ... + 14933882.

It is an arithmetic number, because the mean of its divisors is an integer number (77581555296).

Almost surely, 2^{1110423214433} is an apocalyptic number.

1110423214433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1110423214433 is a deficient number, since it is larger than the sum of its proper divisors (130881670303).

1110423214433 is a wasteful number, since it uses less digits than its factorization.

1110423214433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29793344.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1110423214433 its reverse (3344123240111), we get a palindrome (4454546454544).

The spelling of 1110423214433 in words is "one trillion, one hundred ten billion, four hundred twenty-three million, two hundred fourteen thousand, four hundred thirty-three".