Base | Representation |
---|---|
bin | 11001001111111001000011… |
… | …010100110100111110011010 |
3 | 112120011121221111202001220022 |
4 | 121033321003110310332122 |
5 | 104023313000241112442 |
6 | 1032100314232230442 |
7 | 32250415234324031 |
oct | 3117710324647632 |
9 | 476147844661808 |
10 | 111043214004122 |
11 | 32422187461a84 |
12 | 10554b0383b422 |
13 | 49c643a45232a |
14 | 1d5c73d747718 |
15 | cc874ebc83d2 |
hex | 64fe43534f9a |
111043214004122 has 4 divisors (see below), whose sum is σ = 166564821006186. Its totient is φ = 55521607002060.
The previous prime is 111043214004097. The next prime is 111043214004131. The reversal of 111043214004122 is 221400412340111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 96537482971801 + 14505731032321 = 9825349^2 + 3808639^2 .
It is a super-3 number, since 3×1110432140041223 (a number of 43 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 111043214004091 and 111043214004100.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27760803501029 + ... + 27760803501032.
Almost surely, 2111043214004122 is an apocalyptic number.
111043214004122 is a deficient number, since it is larger than the sum of its proper divisors (55521607002064).
111043214004122 is an equidigital number, since it uses as much as digits as its factorization.
111043214004122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55521607002063.
The product of its (nonzero) digits is 1536, while the sum is 26.
Adding to 111043214004122 its reverse (221400412340111), we get a palindrome (332443626344233).
The spelling of 111043214004122 in words is "one hundred eleven trillion, forty-three billion, two hundred fourteen million, four thousand, one hundred twenty-two".
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