Base | Representation |
---|---|
bin | 1010000110010110110110… |
… | …1110011000001100010111 |
3 | 1110022120012221110121101120 |
4 | 2201211231232120030113 |
5 | 2423413132310200143 |
6 | 35341132010055023 |
7 | 2224155452662065 |
oct | 241455556301427 |
9 | 43276187417346 |
10 | 11104331334423 |
11 | 35a1358604738 |
12 | 12b411611a473 |
13 | 6271983a4472 |
14 | 2a5649959035 |
15 | 143cb0cb7383 |
hex | a196db98317 |
11104331334423 has 16 divisors (see below), whose sum is σ = 14826385000416. Its totient is φ = 7392589701120.
The previous prime is 11104331334329. The next prime is 11104331334469. The reversal of 11104331334423 is 32443313340111.
11104331334423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11104331334423 - 29 = 11104331333911 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11104331334623) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5391543 + ... + 7160823.
It is an arithmetic number, because the mean of its divisors is an integer number (926649062526).
Almost surely, 211104331334423 is an apocalyptic number.
11104331334423 is a deficient number, since it is larger than the sum of its proper divisors (3722053665993).
11104331334423 is a wasteful number, since it uses less digits than its factorization.
11104331334423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1772194.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 11104331334423 its reverse (32443313340111), we get a palindrome (43547644674534).
The spelling of 11104331334423 in words is "eleven trillion, one hundred four billion, three hundred thirty-one million, three hundred thirty-four thousand, four hundred twenty-three".
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