11104421133121 has 4 divisors (see below), whose sum is σ = 11104944676144. Its totient is φ = 11103897590100.

The previous prime is 11104421133103. The next prime is 11104421133161. The reversal of 11104421133121 is 12133112440111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11104421133121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11104421133161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 261739695 + ... + 261782116.

It is an arithmetic number, because the mean of its divisors is an integer number (2776236169036).

Almost surely, 2^{11104421133121} is an apocalyptic number.

It is an amenable number.

11104421133121 is a deficient number, since it is larger than the sum of its proper divisors (523543023).

11104421133121 is an equidigital number, since it uses as much as digits as its factorization.

11104421133121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 523543022.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 11104421133121 its reverse (12133112440111), we get a palindrome (23237533573232).

The spelling of 11104421133121 in words is "eleven trillion, one hundred four billion, four hundred twenty-one million, one hundred thirty-three thousand, one hundred twenty-one".