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11105245313407 = 71586463616201
BaseRepresentation
bin1010000110011010010000…
…1100111011100101111111
31110022122120122021112212001
42201212210030323211333
52423422020300012112
635341402415523131
72224220221451620
oct241464414734577
943278518245761
1011105245313407
1135a1787514673
1212b43302294a7
136272b285382b
142a56d50b3a47
15143d16155c57
hexa19a433b97f

11105245313407 has 4 divisors (see below), whose sum is σ = 12691708929616. Its totient is φ = 9518781697200.

The previous prime is 11105245313401. The next prime is 11105245313419. The reversal of 11105245313407 is 70431354250111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11105245313407 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11105245313401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 793231808094 + ... + 793231808107.

It is an arithmetic number, because the mean of its divisors is an integer number (3172927232404).

Almost surely, 211105245313407 is an apocalyptic number.

11105245313407 is a deficient number, since it is larger than the sum of its proper divisors (1586463616209).

11105245313407 is an equidigital number, since it uses as much as digits as its factorization.

11105245313407 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1586463616208.

The product of its (nonzero) digits is 50400, while the sum is 37.

Adding to 11105245313407 its reverse (70431354250111), we get a palindrome (81536599563518).

The spelling of 11105245313407 in words is "eleven trillion, one hundred five billion, two hundred forty-five million, three hundred thirteen thousand, four hundred seven".

Divisors: 1 7 1586463616201 11105245313407