Base | Representation |
---|---|
bin | 1010000110011010010000… |
… | …1100111011100101111111 |
3 | 1110022122120122021112212001 |
4 | 2201212210030323211333 |
5 | 2423422020300012112 |
6 | 35341402415523131 |
7 | 2224220221451620 |
oct | 241464414734577 |
9 | 43278518245761 |
10 | 11105245313407 |
11 | 35a1787514673 |
12 | 12b43302294a7 |
13 | 6272b285382b |
14 | 2a56d50b3a47 |
15 | 143d16155c57 |
hex | a19a433b97f |
11105245313407 has 4 divisors (see below), whose sum is σ = 12691708929616. Its totient is φ = 9518781697200.
The previous prime is 11105245313401. The next prime is 11105245313419. The reversal of 11105245313407 is 70431354250111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11105245313407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11105245313401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 793231808094 + ... + 793231808107.
It is an arithmetic number, because the mean of its divisors is an integer number (3172927232404).
Almost surely, 211105245313407 is an apocalyptic number.
11105245313407 is a deficient number, since it is larger than the sum of its proper divisors (1586463616209).
11105245313407 is an equidigital number, since it uses as much as digits as its factorization.
11105245313407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1586463616208.
The product of its (nonzero) digits is 50400, while the sum is 37.
Adding to 11105245313407 its reverse (70431354250111), we get a palindrome (81536599563518).
The spelling of 11105245313407 in words is "eleven trillion, one hundred five billion, two hundred forty-five million, three hundred thirteen thousand, four hundred seven".
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