Base | Representation |
---|---|
bin | 10000001010101100110… |
… | …101010010010011100101 |
3 | 10221012200120210020200222 |
4 | 100022230311102103211 |
5 | 121200312302242013 |
6 | 2210215323414125 |
7 | 143160434326211 |
oct | 20125465222345 |
9 | 3835616706628 |
10 | 1111001212133 |
11 | 39919a24754a |
12 | 15b3a0084345 |
13 | 809c8038557 |
14 | 3bab65b1941 |
15 | 1dd766ce508 |
hex | 102acd524e5 |
1111001212133 has 4 divisors (see below), whose sum is σ = 1169474960160. Its totient is φ = 1052527464108.
The previous prime is 1111001212129. The next prime is 1111001212231. The reversal of 1111001212133 is 3312121001111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1111001212133 - 22 = 1111001212129 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1111001242133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29236873985 + ... + 29236874022.
It is an arithmetic number, because the mean of its divisors is an integer number (292368740040).
Almost surely, 21111001212133 is an apocalyptic number.
It is an amenable number.
1111001212133 is a deficient number, since it is larger than the sum of its proper divisors (58473748027).
1111001212133 is an equidigital number, since it uses as much as digits as its factorization.
1111001212133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58473748026.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 1111001212133 its reverse (3312121001111), we get a palindrome (4423122213244).
The spelling of 1111001212133 in words is "one trillion, one hundred eleven billion, one million, two hundred twelve thousand, one hundred thirty-three".
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