111100300130023 has 4 divisors (see below), whose sum is σ = 111152191911768. Its totient is φ = 111048408348280.

The previous prime is 111100300130003. The next prime is 111100300130033. The reversal of 111100300130023 is 320031003001111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 111100300130023 - 2¹³ = 111100300121831 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111100300129979 and 111100300130006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111100300130003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25945887661 + ... + 25945891942.

It is an arithmetic number, because the mean of its divisors is an integer number (27788047977942).

Almost surely, 2^{111100300130023} is an apocalyptic number.

111100300130023 is a deficient number, since it is larger than the sum of its proper divisors (51891781745).

111100300130023 is an equidigital number, since it uses as much as digits as its factorization.

111100300130023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51891781744.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 111100300130023 its reverse (320031003001111), we get a palindrome (431131303131134).

The spelling of 111100300130023 in words is "one hundred eleven trillion, one hundred billion, three hundred million, one hundred thirty thousand, twenty-three".