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11110330020031 = 111010030001821
BaseRepresentation
bin1010000110101101001101…
…0001100011000010111111
31110100010201000001102001121
42201223103101203002333
52424012423441120111
635344003134451411
72224460222654314
oct241532321430277
943303630042047
1011110330020031
1135a3956717a50
1212b530b063b67
136279130ccb88
142a5a58504d0b
15144012740871
hexa1ad34630bf

11110330020031 has 4 divisors (see below), whose sum is σ = 12120360021864. Its totient is φ = 10100300018200.

The previous prime is 11110330020017. The next prime is 11110330020067. The reversal of 11110330020031 is 13002003301111.

11110330020031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11110330020031 - 29 = 11110330019519 is a prime.

It is a super-2 number, since 2×111103300200312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11110330019987 and 11110330020014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11110330021031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 505015000900 + ... + 505015000921.

It is an arithmetic number, because the mean of its divisors is an integer number (3030090005466).

Almost surely, 211110330020031 is an apocalyptic number.

11110330020031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

11110330020031 is a deficient number, since it is larger than the sum of its proper divisors (1010030001833).

11110330020031 is a wasteful number, since it uses less digits than its factorization.

11110330020031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1010030001832.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11110330020031 its reverse (13002003301111), we get a palindrome (24112333321142).

The spelling of 11110330020031 in words is "eleven trillion, one hundred ten billion, three hundred thirty million, twenty thousand, thirty-one".

Divisors: 1 11 1010030001821 11110330020031