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111103400143 = 5913913547543
BaseRepresentation
bin110011101111001000…
…1110101100011001111
3101121202222122111211001
41213132101311203033
53310014432301033
6123012403241131
711012150214331
oct1473621654317
9347688574731
10111103400143
1143133a77a5a
12196483791a7
13a627c9b3b8
14553d969451
152d53e00e7d
hex19de4758cf

111103400143 has 8 divisors (see below), whose sum is σ = 113799369600. Its totient is φ = 108434526168.

The previous prime is 111103400117. The next prime is 111103400153. The reversal of 111103400143 is 341004301111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111103400143 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 111103400143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111103400113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6765571 + ... + 6781972.

It is an arithmetic number, because the mean of its divisors is an integer number (14224921200).

Almost surely, 2111103400143 is an apocalyptic number.

111103400143 is a deficient number, since it is larger than the sum of its proper divisors (2695969457).

111103400143 is a wasteful number, since it uses less digits than its factorization.

111103400143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13547741.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 111103400143 its reverse (341004301111), we get a palindrome (452107701254).

The spelling of 111103400143 in words is "one hundred eleven billion, one hundred three million, four hundred thousand, one hundred forty-three".

Divisors: 1 59 139 8201 13547543 799305037 1883108477 111103400143