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11110424807 = 28097395431
BaseRepresentation
bin10100101100011101…
…11010000011100111
31001200022020001121002
422112032322003213
5140223232043212
65034250543515
7542220024026
oct122616720347
931608201532
1011110424807
1147915aa669
1221a0a37b9b
131080a7b181
147758168bd
15450602ac2
hex2963ba0e7

11110424807 has 4 divisors (see below), whose sum is σ = 11110848336. Its totient is φ = 11110001280.

The previous prime is 11110424803. The next prime is 11110424833. The reversal of 11110424807 is 70842401111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11110424807 - 22 = 11110424803 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11110424807.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11110424803) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 169619 + ... + 225812.

It is an arithmetic number, because the mean of its divisors is an integer number (2777712084).

Almost surely, 211110424807 is an apocalyptic number.

11110424807 is a deficient number, since it is larger than the sum of its proper divisors (423529).

11110424807 is an equidigital number, since it uses as much as digits as its factorization.

11110424807 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 423528.

The product of its (nonzero) digits is 1792, while the sum is 29.

Adding to 11110424807 its sum of digits (29), we get a square (11110424836 = 1054062).

Adding to 11110424807 its reverse (70842401111), we get a palindrome (81952825918).

The spelling of 11110424807 in words is "eleven billion, one hundred ten million, four hundred twenty-four thousand, eight hundred seven".

Divisors: 1 28097 395431 11110424807