11111011020013 has 4 divisors (see below), whose sum is σ = 11469430730368. Its totient is φ = 10752591309660.

The previous prime is 11111011019963. The next prime is 11111011020023. The reversal of 11111011020013 is 31002011011111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11111011020013 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11111011019975 and 11111011020002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11111011020023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 179209855131 + ... + 179209855192.

It is an arithmetic number, because the mean of its divisors is an integer number (2867357682592).

Almost surely, 2^{11111011020013} is an apocalyptic number.

It is an amenable number.

11111011020013 is a deficient number, since it is larger than the sum of its proper divisors (358419710355).

11111011020013 is an equidigital number, since it uses as much as digits as its factorization.

11111011020013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 358419710354.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 11111011020013 its reverse (31002011011111), we get a palindrome (42113022031124).

The spelling of 11111011020013 in words is "eleven trillion, one hundred eleven billion, eleven million, twenty thousand, thirteen".