1111101110141 has 4 divisors (see below), whose sum is σ = 1212110301984. Its totient is φ = 1010091918300.

The previous prime is 1111101110101. The next prime is 1111101110149. The reversal of 1111101110141 is 1410111011111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1111101110141 is a prime.

It is a super-2 number, since 2×1111101110141² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1111101110149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50504595905 + ... + 50504595926.

It is an arithmetic number, because the mean of its divisors is an integer number (303027575496).

Almost surely, 2^{1111101110141} is an apocalyptic number.

1111101110141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1111101110141 is a deficient number, since it is larger than the sum of its proper divisors (101009191843).

1111101110141 is a wasteful number, since it uses less digits than its factorization.

1111101110141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 101009191842.

The product of its (nonzero) digits is 4, while the sum is 14.

Adding to 1111101110141 its reverse (1410111011111), we get a palindrome (2521212121252).

The spelling of 1111101110141 in words is "one trillion, one hundred eleven billion, one hundred one million, one hundred ten thousand, one hundred forty-one".