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11111013303122 = 25555506651561
BaseRepresentation
bin1010000110101111110000…
…0000000100001101010010
31110100012110121202210020202
42201223330000010031102
52424020323401144442
635344155023535202
72224513160532305
oct241537400041522
943305417683222
1011111013303122
1135a4177389717
1212b547ba5a502
136279c18382b5
142a5ac116ab3c
1514405270ec32
hexa1afc004352

11111013303122 has 4 divisors (see below), whose sum is σ = 16666519954686. Its totient is φ = 5555506651560.

The previous prime is 11111013303079. The next prime is 11111013303139. The reversal of 11111013303122 is 22130331011111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 8780844636001 + 2330168667121 = 2963249^2 + 1526489^2 .

It is a junction number, because it is equal to n+sod(n) for n = 11111013303094 and 11111013303103.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2777753325779 + ... + 2777753325782.

Almost surely, 211111013303122 is an apocalyptic number.

11111013303122 is a deficient number, since it is larger than the sum of its proper divisors (5555506651564).

11111013303122 is an equidigital number, since it uses as much as digits as its factorization.

11111013303122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5555506651563.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 11111013303122 its reverse (22130331011111), we get a palindrome (33241344314233).

The spelling of 11111013303122 in words is "eleven trillion, one hundred eleven billion, thirteen million, three hundred three thousand, one hundred twenty-two".

Divisors: 1 2 5555506651561 11111013303122