Base | Representation |
---|---|
bin | 1010000110110000000000… |
… | …0010110011100100000001 |
3 | 1110100012122100101202120021 |
4 | 2201230000002303210001 |
5 | 2424020443232131431 |
6 | 35344205445413441 |
7 | 2224514643206101 |
oct | 241540002634401 |
9 | 43305570352507 |
10 | 11111081130241 |
11 | 35a42016a6194 |
12 | 12b549a70a281 |
13 | 627a028c5aa1 |
14 | 2a5aca185201 |
15 | 14405865bb11 |
hex | a1b000b3901 |
11111081130241 has 16 divisors (see below), whose sum is σ = 11793577593600. Its totient is φ = 10449901340928.
The previous prime is 11111081130217. The next prime is 11111081130293. The reversal of 11111081130241 is 14203118011111.
It is a cyclic number.
It is not a de Polignac number, because 11111081130241 - 25 = 11111081130209 is a prime.
It is a super-2 number, since 2×111110811302412 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11111081130041) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11681656 + ... + 12596953.
It is an arithmetic number, because the mean of its divisors is an integer number (737098599600).
Almost surely, 211111081130241 is an apocalyptic number.
It is an amenable number.
11111081130241 is a deficient number, since it is larger than the sum of its proper divisors (682496463359).
11111081130241 is a wasteful number, since it uses less digits than its factorization.
11111081130241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24279048.
The product of its (nonzero) digits is 192, while the sum is 25.
Adding to 11111081130241 its reverse (14203118011111), we get a palindrome (25314199141352).
The spelling of 11111081130241 in words is "eleven trillion, one hundred eleven billion, eighty-one million, one hundred thirty thousand, two hundred forty-one".
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