11111141000503 has 4 divisors (see below), whose sum is σ = 11117209348048. Its totient is φ = 11105072652960.

The previous prime is 11111141000501. The next prime is 11111141000521. The reversal of 11111141000503 is 30500014111111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11111141000503 - 2¹ = 11111141000501 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11111141000501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3034171026 + ... + 3034174687.

It is an arithmetic number, because the mean of its divisors is an integer number (2779302337012).

Almost surely, 2^{11111141000503} is an apocalyptic number.

11111141000503 is a deficient number, since it is larger than the sum of its proper divisors (6068347545).

11111141000503 is an equidigital number, since it uses as much as digits as its factorization.

11111141000503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6068347544.

The product of its (nonzero) digits is 60, while the sum is 19.

Adding to 11111141000503 its reverse (30500014111111), we get a palindrome (41611155111614).

The spelling of 11111141000503 in words is "eleven trillion, one hundred eleven billion, one hundred forty-one million, five hundred three", and thus it is an aban number.